0=-16t^2+4100

Solution for 0=-16t^2+4100 equation:

0=-16t^2+4100

We move all terms to the left:

0-(-16t^2+4100)=0

We add all the numbers together, and all the variables

-(-16t^2+4100)=0

We get rid of parentheses

16t^2-4100=0

a = 16; b = 0; c = -4100;
Δ = b2-4ac
Δ = 02-4·16·(-4100)
Δ = 262400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{262400}=\sqrt{6400*41}=\sqrt{6400}*\sqrt{41}=80\sqrt{41}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{41}}{2*16}=\frac{0-80\sqrt{41}}{32}
=-\frac{80\sqrt{41}}{32}
=-\frac{5\sqrt{41}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{41}}{2*16}=\frac{0+80\sqrt{41}}{32}
=\frac{80\sqrt{41}}{32}
=\frac{5\sqrt{41}}{2}
$